how heavy would 100kgs of doosul be on a cold day?
Adz
New Member
It's a nice try nobber, but it's bollox mate 
Diesel weighs a bit less than water - approx 7lBs per US gallon, 8.4lBs per imperial gallon or 0.84 Kgs/litre. Land Rover 90 tank is 55 litres so 46Kgs.
Exact calcs for diesel depend on the specific gravity - which changes through the year, typically, because of differing requirements for fuels in summer and winter ambient temps.
Riddle me this - if it were heavier than water, why would it float as it does instead of sinking?
Diesel weighs a bit less than water - approx 7lBs per US gallon, 8.4lBs per imperial gallon or 0.84 Kgs/litre. Land Rover 90 tank is 55 litres so 46Kgs.
Exact calcs for diesel depend on the specific gravity - which changes through the year, typically, because of differing requirements for fuels in summer and winter ambient temps.
Riddle me this - if it were heavier than water, why would it float as it does instead of sinking?
Adz
New Member
Oh yes you can, you just can't compress liquid denzil.
by george i think i have it..
The flame temperature can also be predicted from the First Law of Thermodynamics given by
En[h°+Dh] = En[h°+Dh] +Q
r i f i p i f i l
where ni is moles of species i per mole of fuel,
hf°; the enthalpy of formation at standard temperature,
h = h(T) - h(T° = C p(T - T°,
T° is standard temperature,
R and P are reactant and product.
Ql represents the heat loss per mole of fuel consumed.
In this experiment the flame is established on a flat flame burner as shown in Figure 2. The burner is water cooled and the heat loss from the flame to the burner can be measured by measuring the difference in enthalpy between the inlet and outlet cooling water.
q = mCw(To - Ti)
where q is the heat loss per unit time, m is the mass flow rate, Cw the specific heat of the cooling fluid (water) and T o and Ti are the outlet and inlet temperatures, respectively.
The flame temperature can also be predicted from the First Law of Thermodynamics given by
En[h°+Dh] = En[h°+Dh] +Q
r i f i p i f i l
where ni is moles of species i per mole of fuel,
hf°; the enthalpy of formation at standard temperature,
h = h(T) - h(T°
= C p(T - T°, T° is standard temperature,
R and P are reactant and product.
Ql represents the heat loss per mole of fuel consumed.
In this experiment the flame is established on a flat flame burner as shown in Figure 2. The burner is water cooled and the heat loss from the flame to the burner can be measured by measuring the difference in enthalpy between the inlet and outlet cooling water.
q = mCw(To - Ti)
where q is the heat loss per unit time, m is the mass flow rate, Cw the specific heat of the cooling fluid (water) and T o and Ti are the outlet and inlet temperatures, respectively.
