B34R
Active Member
Sorry but yer theory is wrong. ABS brake pulses wheels to assist directional stability which is it's first point of use, but does help brake sharper due to the on/oft repeating pulse as a secondary element when brake force applied changes from on to pulsing. All 4 wheels are braked when the foot brake is applied. Only skidding wheels are brake pulsed by the abs, on an if and when basis of it happening. ABS is quick to activate if within the correct speed range. This reaction is so quick the prop wouldn't have enough time to slow to increase the differing speed with the other prop.
I think you missed my point entirely - I'm not talking about the point past the point of lockup where the ABS kicks in. (I'm entirely aware of how ABS works!)
My point is that with no centre diff the drivetrain prevents a single wheel or an entire axle getting to the point of locking while the vehicle is at speed.
If you take a model of the drive train, the VCU tries to force the front axle to rotate at the same speed as the rear axle.
This means if you stand on the brakes really hard in a situation that would normally lock both front wheels - you're in a situation where the brakes have stopped the front diff, but the rear wheels still have traction and are turning. In this situation you have Rear (200 RPM) = VCU LOCK = Front (0 RPM)
Which means you end up in a torque fight through the VCU where the rear axle is trying to force the front axle to not keep turning and the locked front axle is trying to bring the rear axle to a complete stop. Which means that when you REALLY stand on the brakes to the point of lockup the VCU is redistributing the brake force through all four wheels.
With me so far?
When you apply this one step further...
Remember a differential is a basic equation of input RPM x 2 = left rpm + right rpm
In a normal FWD car this equals gearbox output RPM x 2 = left wheel + right wheel so when you stand on the brakes and lock up one front wheel there's an escape route for the extra rpms. IE Your engine RPMS will suddenly drop because a wheel is locked so theres a torque escape route.
The freelander VCU drivetrain is a special case though - you cannot lock just one wheel, you'd HAVE to lock one front and one back at the same time to compensate. If you break it down to a mathematical model (and assume that the front and rear axles are the same ratio for the time being) you're in a situation where:
Front Left Wheel RPM + Front Right Wheel RPM = Rear Left Wheel RPM + Rear Right Wheel RPM
So if you're spinning at 200 RPM:
200 + 200 = 200 + 200
So if a front wheel attempts to lock you end up in a situation:
200 + 0 != 200 + 200
And if you go back to the example above trying to lock a single axle you get:
0 + 0 != 200 + 200
In reality it'll allow a certain amount of slip, BUT, it will do it's damndest to prevent a lock OR transmit a sympathetic lock to another axle.
The overall effect of this will be that the drive train tries to eliminate an axle starting to move towards not spinning at the same speed as the others - effectively redistributing any excess brake force from the front axle to the back axle. (I'm betting that's another reason they altered the ratios front to back, to stop the front axle transmitting a complete lock to the back axle in an emergency.)
The freelander is a special case in this - the tratter boys won't see this effect because they have a centre diff which means if you lock an axle you get the same effect as a purely FWD car - the escaping torque goes back to the engine.