JohnM70 said:

If we assume the battery is producing 12VDC with a constant flow rate of 7 within the cross-ratio inductance limits of -8 to +12, a simple calculation using the vector approach capacitance factor of .237, multiplied by the overall impedance of the entire circuit, less the impedance of the ignition circuit measured in Floretts and then converted to Ohms (assuming an overall reduction in Joules of 19), the result will be so easy to see, you'll wonder why it was so hard in the first place.

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The Mad Hat Man said:

to the point and succinct.

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JohnM70 said:

If we assume the battery is producing 12VDC with a constant flow rate of 7 within the cross-ratio inductance limits of -8 to +12, a simple calculation using the vector approach capacitance factor of .237, multiplied by the overall impedance of the entire circuit, less the impedance of the ignition circuit measured in Floretts and then converted to Ohms (assuming an overall reduction in Joules of 19), the result will be so easy to see, you'll wonder why it was so hard in the first place.

Click to expand...

Silverlandy said:

Oh I get it now!

not

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