My baby's "hand-drawn" pyrography on 3 oak chopping boards.
and...
and...
Isn't she a clever girl?
No stencils or "lasers" @My Old Landy
and...
and...
Isn't she a clever girl?
No stencils or "lasers" @My Old Landy
My baby's "hand-drawn" pyrography on 3 oak chopping boards.
View attachment 325757
and...
View attachment 325758
and...
View attachment 325759
Isn't she a clever girl?
No stencils or "lasers" @My Old Landy
Very good talent, they are lovely.
Thank You, I will let her know.Very good talent, they are lovely.
This one is for @kevstar primarily, seeing as he has done it recently. But I laughed until the tears ran down my face, then asked the question! At the bottom.
"Just to put a toe in the water so to speak , In November I will be replacing my kitchen , therefore I wonder as it is in good condition ,made by a company called Elizabeth Anne , shaker styleIncluding a matching Neff dishwasher. Is any one interested in having it for about £1 ,500 Ono? Photos will appear , viewing always available.
cecilia d.
•Purewell & Stanpit•1d
A bargain for someone if they can fit it themselves!
Like
John H.
•Ameysford•Now
Is that the price removed or would you like us to take it all out for you?
Like
I hate kitchens
That's the price for it removed. "and taken away". ?
She also will be flogging a Rangemaster cooker. Am now very much wondering why anyone would want to get rid of one of those as we love our equivalent.
No one on Nextdoor seems to have twigged the wind up yet.
What rangemaster is it & what size is it.
So I woz right first time then? Flipping miracle.
I wasn't sure that A-D and D-E would be equal as although the angle was bisected, the triangle is not isoceles, so if the sides are of different lengths then the two bits of A-E might not be the same, hence my remark.
Eventually I'll cheat and look it all up on the site the puzzle comes from.
I will just whizz past em cause ive got other things id rather do then fry my matter, id rather have somit in batter.
Even those who comment on the problem, and usually do get it right, most of them, cannot agree.
I was always taught in Maths to exaggerate a case to see where it leads.
So, imagine if AE was much much longer. With the angles at B, even though always equal, would their bisector always touch AE at its mid point? I somehow don't think so. I think ED would always be shorter than DA, As I said, BAE is not an isoceles triangle. Only if AB=AE could we be sure that the angle at A bisector would always divide AE equally.
Especially ones with Copper in!!!I hate kitchens
